JohnH
Well-Known Member
hi @Echelon ,
If you were trying to get a lower resonance, you'd need a larger cap and larger inductor value. The resonant frequency is
F = 1/ (2pi.sqrt (L.C))
If you do use an open back, the tone you get has the resonance of that real cab in any case, M2 or M3. Its just the response in terms of over-driven bass harmonics will be as for the closed back. It'd be a very subtle change, given that even bypassing the bass circuit makes hardly any difference.
I think if you build it as drawn, but with a switch to bypass the resonant circuit, then you'll have plenty to explore. Or, just do M2 at least to start with.
An open cab might have a resonance at about 80hz. So its not even relevant until you are on the last few lowest notes on your low E string. And they will come through in any case, but the real character of the tone, for which a reactive circuit helps, is in the high mids and highs, covered by the small coil and the way its set up in the circuit.
If you were trying to get a lower resonance, you'd need a larger cap and larger inductor value. The resonant frequency is
F = 1/ (2pi.sqrt (L.C))
If you do use an open back, the tone you get has the resonance of that real cab in any case, M2 or M3. Its just the response in terms of over-driven bass harmonics will be as for the closed back. It'd be a very subtle change, given that even bypassing the bass circuit makes hardly any difference.
I think if you build it as drawn, but with a switch to bypass the resonant circuit, then you'll have plenty to explore. Or, just do M2 at least to start with.
An open cab might have a resonance at about 80hz. So its not even relevant until you are on the last few lowest notes on your low E string. And they will come through in any case, but the real character of the tone, for which a reactive circuit helps, is in the high mids and highs, covered by the small coil and the way its set up in the circuit.