id say 720hz is the frequency where the impedance of the cap equals the resistor.
1/(2.Pi.F.C) = R
1/(2.Pi x 720 x 470E-12) = 470000000
The cap has a cut off frequency independent of the resister.
I know a typical Marshall 470k/470pF gives a corner frequency of about 720Hz, but does anyone know the math to get there?
Much appreciated...wak
The impedance of the cap equals the resistance of the resistor and the phase shift is 45 degrees and your formula is correct, but your calculation is off.
id say 720hz is the frequency where the impedance of the cap equals the resistor.
1/(2.Pi.F.C) = R
1/(2.Pi x 720 x 470E-12) = 470000000
Thats what I was gonna say......1 / 6.28 x 470pF x 470k = 720.8Hz
1 / 6.28 x 470pF x 470k = 720.8Hz
2 x Pi = 6.28Mickey...where does the 6.28 come from?
Is it the impedance coming into the peaker?
Also, what if there's no reference to ground....
say a 47k bootstrapped with a 2.2uF in the signal path just like a coupling cap or grid stopper.
2 x Pi = 6.28
1 / 6.28 x 2.2uF x 47k = 1.54Hz
2 x Pi = 6.28
1 / 6.28 x 2.2uF x 47k = 1.54Hz
You gotta do your sequence right.I'm getting...
1/6.28 =0.1592356
x 2.2 = 0.3503183
x 47000 = 16,464.96 ???
Sorry,
it's been a LONG time since I've used any advanced math.
2 x Pi = 6.28
1 / 6.28 x 2.2uF x 47k = 1.54Hz